Skip to content
Snippets Groups Projects
Commit 42bbde41 authored by Brad King's avatar Brad King Committed by Kitware Robot
Browse files

Merge topic 'cmalgorithm-modernize-cmremoveduplicates'


bf1e7330 cmAlgorithms: Refactor cmRemoveDuplicates

Acked-by: default avatarKitware Robot <kwrobot@kitware.com>
Merge-request: !3029
parents 18ff7cc3 bf1e7330
No related branches found
No related tags found
No related merge requests found
......@@ -233,27 +233,45 @@ typename Range::const_iterator cmRemoveMatching(Range& r, MatchRange const& m)
ContainerAlgorithms::BinarySearcher<MatchRange>(m));
}
template <typename Range>
typename Range::const_iterator cmRemoveDuplicates(Range& r)
template <typename ForwardIterator>
ForwardIterator cmRemoveDuplicates(ForwardIterator first, ForwardIterator last)
{
typedef typename Range::value_type T;
std::unordered_set<T> unique;
std::vector<size_t> indices;
size_t count = 0;
const typename Range::const_iterator end = r.end();
for (typename Range::const_iterator it = r.begin(); it != end;
++it, ++count) {
const typename std::unordered_set<T>::iterator occur = unique.find(*it);
if (occur == unique.end()) {
unique.insert(*it);
} else {
indices.push_back(count);
using Value = typename std::iterator_traits<ForwardIterator>::value_type;
using Hash = struct
{
std::size_t operator()(ForwardIterator it) const
{
return std::hash<Value>{}(*it);
}
};
using Equal = struct
{
bool operator()(ForwardIterator it1, ForwardIterator it2) const
{
return *it1 == *it2;
}
};
std::unordered_set<ForwardIterator, Hash, Equal> uniq;
ForwardIterator result = first;
while (first != last) {
if (uniq.find(first) == uniq.end()) {
if (result != first) {
*result = std::move(*first);
}
uniq.insert(result);
++result;
}
++first;
}
if (indices.empty()) {
return end;
}
return cmRemoveIndices(r, indices);
return result;
}
template <typename Range>
typename Range::const_iterator cmRemoveDuplicates(Range& r)
{
return cmRemoveDuplicates(r.begin(), r.end());
}
template <typename Range>
......
0% Loading or .
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or to comment